A Solution Must Be 14% Insecticide. To Make 5 Gallons Of This Solution How Much Insecticide Must You (2024)

The angle BOC has a measure of 50 degrees

How to evaluate the measure of the angle?

From the question, the given parameters about the angles are:

OA-OB-OCAOB = 9x + 20BOC = 7x - 6AOC = 142

The above parameters implies that

AOC = AOB + BOC

Next, we substitute the angle measurements in the above equation

So, we have

142 = 9x + 20 + 7x - 6

Evaluate the like terms

So, we have the following equation

142 = 16x + 14

Evaluate the like terms again

So, we have the following equation

16x = 128

Divide both sides by 16

x = 8

Substitute x = 8 in BOC = 7x - 6

BOC = 7 x 8 - 6

Evaluate

BOC = 50

Hence, the measure of the angle is 50 degrees

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Step-by-step explanation:

Original Equation:

[tex]x^2+5=0[/tex]

Subtract 5 from both sides

[tex]x^2 = -5[/tex]

Take the square root of both sides

[tex]x=\pm\sqrt{-5}[/tex]

Simplify

[tex]x=\pm i\sqrt{5}[/tex]

Thus we have two non-real solutions, and zero real solutions. This implies that the graph will never cross the x-axis when graphing the function out, because it has no real solutions.

Given:

There are 6 roses in a vase of 14 flowers.

Required:

To find the ratio of all flowers in the vase to daisies.

Explanation:

The total number of daisies in the vase are

[tex]\begin{gathered} =14-6 \\ =8 \end{gathered}[/tex]

So the ratio of all flowers in the vase to daisies is,

[tex]14:8[/tex][tex]7:4[/tex]

Final Answer:

[tex]7:4[/tex]

f(x)= x^2

To shift 5 units to the right subtract 5 to x .

g(x)= (x-5)^2

The equations that represent the diagram given are 7 + 8h = 167, 8h = 160

Equation that represent the diagram

To find the equation that represent the situation, we should simply count the number h present in the diagram, add it to 7 and equate the entire length to 167 which is the length of the tube.

This can be represented mathematically as

[tex]7 + h + h + h + h + h + h + h + h = 167[/tex]

we can simplify this further as

[tex]7 + h + h + h + h + h + h + h + h = 167\\7 + 8h = 167\\[/tex]

This can also be simplified as

[tex]7 + 8h = 167\\8h = 167 - 7\\8h = 160[/tex]

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EXPLANATION

The coordinate for point A is x=9

start by calculating the 7% of all the sales

[tex]\begin{gathered} \text{Comission}=(0.07)\cdot412,454 \\ \text{comission}=28,871.78 \end{gathered}[/tex]

Calculate the bonus from the comission

[tex]\begin{gathered} \text{Bonus}=(28,871.78)\cdot(0.05) \\ \text{Bonus}=1,443.59 \end{gathered}[/tex]

The total gross pay will be the addition between the comission and bonus

[tex]\begin{gathered} G.\text{ Income=28,871.78+1,443.59} \\ G\text{. income=30,315.37} \end{gathered}[/tex]

The monthly income will be the division between 12 months of the year

[tex]\begin{gathered} \text{Monthly income} \\ \frac{30,315.37}{12}=2526.28 \end{gathered}[/tex]

Answer:

10 to the second power

[tex]10^2[/tex]

Explanation:

Let the unknown value be x

The given expression can be rewritten as:

[tex]x\times0.006=0.6[/tex]

Express as a fraction;

[tex]\begin{gathered} x\times\frac{6}{1000}=\frac{6}{10} \\ \frac{6x}{1000}=\frac{6}{10} \\ \end{gathered}[/tex]

Cross multiply

[tex]\begin{gathered} 6x\times10=6\times1000 \\ 60x=6000 \\ x=\frac{6000}{60} \\ x=100 \\ x=10^2 \end{gathered}[/tex]

Hence the required unknown number in the exponential power of 10 is 10^2

To find the volume of the computer, we just have to multiply each coordinate.

[tex]\begin{gathered} V=3in\times3in\times3.6in \\ V=32.4in^3 \end{gathered}[/tex]Hence, the volume is 32.4 cubic inches.

The slope of the red line is 5. The correct answer is option B. 5

Two parallel lines, always have the same slope. Since the green and red line are parallels and the green line has slope 5, the slope of the red line is also 5.

Answer:

she has left 28 unsolved problem or whatever it is

Step-by-step explanation:

48:12=4

4x7=27

Answer:

length = 46cm

Step-by-step explanation:

The length of a rectangle is double its width. If the rectangle has a perimeter of 138cm, find its length (in cm).

p = 2l + 2w

when l = 2w, substitute in to equation:

138 = 2(2w) + 2w

138 = 4w + 2w

138 = 6w

divide both sides by 6:

138/6 = 6w/6

so width = 23cm

and we know that length = 2 width so:

length = 23cm × 2

length = 46cm

In order to determine the weighs of the boxes, name x as the larger box and y as the smaller one.

Then, based on the given situation, you can write the following equations:

3x + 2y = 86

8x + 4y = 209

Solve the previous system of equations as follow:

Multiply the first equation by -2 and add the result to the second equation:

(3x + 2y = 86)(-2)

-6x - 4y = -172

8x + 4y = 209

-6x - 4y = -172

2x = 37

Solve the previous equation for x by dividing by 2 both sides:

x = 37/2

x = 18.5

Next, replace the previous value of x into any of the equations of the system, for instance, into the first equation, and solve for y:

3x + 2y = 86

3(18.5) + 2y = 86

55.5 + 2y = 86

2y = 86 - 55.5

2y = 30.5

y = 30.5/2

y = 15.25

Hence, the weighs of the boxes are:

larger box = 18.5 kg

smaller box = 15.25 kg

Answer:Dear Mikey,

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Call 923-456-2483

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Step-by-step explanation:

Answer:

The answer is A

Answer it is c because when you multiply 12 x 5 you get 60 right so round up to the nearest number 62 an u can't subtract or divide you won't get a or b

Given:

9x+5y=28

5x+9y=56

Required:

To calculate the solution of the system

Explanation:

Rearrange like terms to the same side of the equation

[tex]\begin{gathered} 5x=28-9x \\ \\ 5x+9y=56 \\ \\ y=\frac{28-9x}{5} \\ \\ 5x+9y=56 \\ \\ substitute\text{ in the equation } \\ \\ 5x+9\times\frac{28-9x}{5}=56 \\ \\ x=\frac{-1}{2} \end{gathered}[/tex][tex]\begin{gathered} substitute\text{ value in y} \\ \\ y=\frac{28-9\times(\frac{-1}{2}}{5} \\ \\ y=\frac{13}{2} \end{gathered}[/tex]

Required answer:

Option B

The formula for the confidence interval is;

Where:

[tex]undefined[/tex]

Given:

The mean is 25.4, the sample size n is 89, the standard deviation s is 2.4.

a. For the 95% confidence interval, the z-score for a 95% interval is 1.96.

Therefore, the 95% confidence interval is;

[tex]\begin{gathered} CI=25.4-1.96\frac{2.4}{\sqrt[]{89}}<\operatorname{mean}<25.4+1.96\frac{2.4}{\sqrt[]{89}} \\ CI=24.90<\operatorname{mean}<25.90 \end{gathered}[/tex]

Answer: (24.90, 25.90)

b. For the 90% confidence interval, the z-score for a 90% interval is 1.645.

Therefore, the 90% confidence interval is;

[tex]\begin{gathered} CI=25.4-1.645\frac{2.4}{\sqrt[]{89}}<\operatorname{mean}<25.4+1.645\frac{2.4}{\sqrt[]{89}} \\ CI=24.98<\operatorname{mean}<25.82 \end{gathered}[/tex]

Answer: (24.98, 25.82)

c. For the 99% confidence interval, the z-score for a 99% interval is 2.576.

Therefore, the 99% confidence interval is;

[tex]\begin{gathered} CI=25.4-2.576\frac{2.4}{\sqrt[]{89}}<\operatorname{mean}<25.4+2.576\frac{2.4}{\sqrt[]{89}} \\ CI=24.74<\operatorname{mean}<26.06 \end{gathered}[/tex]

Answer: (24.74, 26.06)

Given:

Mean = 200

Standard deviation = 26

a) Find the standard error for a sample size of 10:

[tex]E=\frac{\sigma}{\sqrt{N}}[/tex]

Substitute the values:

[tex]E=\frac{26}{\sqrt{10}}=8.22[/tex]

Answer: 8.22

We need to isolate on the equation

[tex]8+(z\times1)=0[/tex]

since any number multiplied by one is the same, then z times 1 is z, so we can write

[tex]8+z=0[/tex]

Now, we can add -8 to both side and get

[tex]8-8+z=-8[/tex]

since 8 - 8 is zero, we have

[tex]z=-8[/tex]

then, z is equal to -8.

The answer is ..

Action movies

The equation which is helpful to determine x, the cost of the labor per hour is 4.25x + 54 = 585.25.

How to form an equation?

Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.

Given that,

x is the labor cost per hour.

The technician worked on the computer for 4.25 hours.

Total labor cost = 4.25x

The total parts cost = $54

The total charged cost = total parts cost + total labor cost

585.25 = 54 + 4.25x

4.25x + 54 = 585.25

Hence "The equation which is helpful to determine x, the cost of the labor per hour is 4.25x + 54 = 585.25".

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The final velocity of the Ferrari will be 84.53 km/h. with an initial velocity of 10 km/h, accelerates at a rate of 50 km/h/min for 3 minutes.

This is a typical question from Newtonian mechanics. To solve this problem we have to convert all the given data into a standard unit like C.G.S.

Now, we will convert 10 km/h and 50 km/h by using the formula. (km/h × 5/18 = m/s )

10 km/h = 10× 5/18 = 2.78 m/s

50 km/h = 50× 5/18 = 13.89 m/sec/min = 0.23 m/s²

3 min = 3 × 60 = 180 sec. ( 1 min = 60 sec )

Now, we have to use the formula from Newton's law of motion,

v = u + at/2 .

Here, u is the initial velocity which is 2.78 m/s.a is the acceleration which is 0.23 m/s²t is the period which is 180 sec. v is the final velocity.

Now we can calculate the final velocity,

v = 2.78 + (0.23 × 180)/2 = 2.78 + 20.7 = 23.48 m/s

Now, we have to calculate the velocity in km/h, which is (23.48 × 5 )/8 = 84.53 km/h. as we know (km/h = m/s ×18/5 ).

Therefore, the final velocity will be 23.48 m/s according to the given inputs and criteria.

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Answer:

The answer to your question is:

False.

Step-by-step explanation:

If prices increase, then no one would want to buy the product. No one would come.

Therefore, the correct answer is;

When prices increase, supply decreases.

Answer: move three units to the left, and 5 units down would be the answer to it

Step-by-step explanation: hope i helped

Scatter drawing plot

Answer:

-15, -5, 0, 10, 25

Step-by-step explanation:

Answer:-

15, -5, 0, 10, 25

Least -> greatest

Step-by-step explanation:

The expression that is equivalent to the expression illustrated is 1/12g - 18.

What is an expression?

It should be noted that an expression is used to show the relationship between the variables.

The expression will be illustrated as:.

= 5/4g - 3 - 7/12g - (1/3g + 15)

= 5/4g - 3 - 7/12g - 1/3g - 15

= 5/4g - 7/12g - 1/3g - 3 - 15

= 15/12g - 7/12g - 4/12g - 18

= 1/12g - 18

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1) [tex]VX=ZX, \angle XVY=\angle XZW[/tex] (given)

2) [tex]\angle X=\angle X[/tex] (reflexive property)

3) [tex]\triangle VXY \equiv \triangle ZXW[/tex] (ASA)